A 3.2 liter sample of gas is at 40 $\circ$ C and 1.0 atmosphere of pressure.If the temperature decreases to 20 $\circ$ C and the pressure decreases to 0.60 atmospheres,what is the new volume in liters?
A) 5.7
B) 5.0
C) 1.8
D) 0.20

Question

Quizplus · Accepted Answer

Using the combined gas law: 
(P1V1/T1) = (P2V2/T2)
Convert temperatures to Kelvin: 
T1 = 40 + 273 = 313 K 
T2 = 20 + 273 = 293 K 
Substitute given values: 
(1.0 atm)(3.2 L)/(313 K) = (0.60 atm)(V2)/(293 K) 
Solve for V2: 
V2 = (1.0 atm)(3.2 L)(293 K)/(313 K)(0.60 atm) = 5.0 L 
Therefore, the new volume is 5.0 liters, which corresponds to choice B.

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