A 30-M Rod Is Pivoted About Its Left End $\degree$ To the Rod and Causes a Cw Torque

A 3.0-m rod is pivoted about its left end.A force of 6.0 N is applied perpendicular to the rod at a distance of 1.2 m from the pivot causing a ccw torque,and a force of 5.2 N is applied at the end of the rod 3.0 m from the pivot.The 5.2 N is at an angle of 30 $\degree$ to the rod and causes a cw torque.What is the net torque about the pivot?

A) 15 N*m
B) 0 N*m
C) -6.3 N*m
D) -0.6 N*m