A baseball pitcher loosens up his pitching arm.He tosses a 0.15-kg ball using only the rotation of his forearm,0.32 m in length,to accelerate the ball.What is the moment of inertia of the ball alone as it moves in a circular arc with a radius of 0.32 m? A)1.5 x 10^-2 kg*m² B)16 x 10^-2 kg*m² C)4.0 x 10^-2 kg*m² D)7.6 x 10^-2kg*m²

Question

Quizplus · Accepted Answer

The moment of inertia of a point mass is given by I = mr^2, where m is the mass and r is the distance from the axis of rotation. In this case, the mass of the ball is 0.15 kg and the radius of rotation is 0.32 m, so the moment of inertia is I = (0.15 kg)(0.32 m)^2 = 1.5 x 10^-2 kg m^2.

A Baseball Pitcher Loosens Up His Pitching Arm