A roller coaster,loaded with passengers,has a mass of 2 000 kg;the radius of curvature of the track at the bottom point of the dip is 24 m.If the vehicle has a speed of 18 m/s at this point,what force is exerted on the vehicle by the track? (g = 9.8 m/s²) A) 2.3 × 10⁴ N B) 4.7 × 10⁴ N C) 3.0 × 10⁴ N D) 1.0 × 10⁴ N

Question

Quizplus · Accepted Answer

The force exerted on the roller coaster by the track can be calculated using the formula: 
Centripetal force = (mass x velocity^2) / radius

Plugging in the given values, we get: 
Centripetal force = (2,000 kg x (18 m/s)^2) / 24 m 
Centripetal force = 4,500 N

Therefore, the force exerted on the vehicle by the track is 4.7 x 10^3 N (rounded to two significant figures). The closest answer choice is B.

A Roller Coaster,loaded with Passengers,has a Mass of 2 000