A 1 200-kg automobile moving at 25 m/s has the brakes applied with a deceleration of 8.0 m/s².How far does the car travel before it stops? A)39 m B)47 m C)55 m D)63 m

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Quizplus · Accepted Answer

Explanation:The equation of motion is:v^2 = u^2 + 2aswhere v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.In this case, v = 0 m/s, u = 25 m/s, a = -8.0 m/s^2, and we want to find s.Substituting these values into the equation, we get:0^2 = 25^2 + 2(-8.0)ss = 39.1 mTherefore, the car travels 39.1 m before it stops.

A 1 200-Kg Automobile Moving at 25 M/s Has the Brakes