A 7.00-kg bowling ball falls from a 2.00-m shelf.Just before hitting the floor,what will be its kinetic energy? (g = 9.80 m/s² and assume air resistance is negligible) A)14.0 J B)19.6 J C)29.4 J D)137 J

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Quizplus · Accepted Answer

The potential energy at the top is converted to kinetic energy at the bottom. Potential energy = mgh = 7.00 kg * 9.80 m/s² * 2.00 m = 137 J. Thus, the kinetic energy just before hitting the floor is 137 J.

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