A baseball catcher puts on an exhibition by catching a 0.15-kg ball dropped from a helicopter at a height of 101 m.What is the speed of the ball just before it hits the catcher's glove 1.0 m above the ground? (g = 9.8 m/s² and ignore air resistance)

Question

Quizplus · Accepted Answer

The speed of the ball can be calculated using the conservation of energy principle. The potential energy at 101 m is converted to kinetic energy at 1 m above the ground. Using the formula v = sqrt(2gh), where h is the height difference (100 m), the speed is approximately 44 m/s.

A Baseball Catcher Puts on an Exhibition by Catching a 0.15-Kg