A force of 100 N is applied to a 50-kg mass in the direction of motion for a distance of 6.0 m and then the force is increased to 150 N for the next 4.0 m.For the 10 m of travel,how much work is done by the varying force?
A)1 200 J
B)1 500 J
C)2 400 J
D)-1 500 J

Question

Quizplus · Accepted Answer

To calculate the work done by the varying force, we need to calculate the work done in two parts:
1) Work done by the 100 N force for 6.0 m
2) Work done by the 150 N force for 4.0 m

For the first part, we can use the formula:
Work = force x distance x cos(theta)
where theta is the angle between the force and the direction of motion (which is 0 degrees in this case).

Work = 100 N x 6.0 m x cos(0)
Work = 600 J

For the second part, we can use the same formula:
Work = force x distance x cos(theta)
But this time, the force is 150 N and the distance is 4.0 m.

Work = 150 N x 4.0 m x cos(0)
Work = 600 J

Therefore, the total work done by the varying force is:
Total work = 600 J + 600 J
Total work = 1 200 J

Therefore, the best choice is A) 1 200 J.

A Force of 100 N Is Applied to a 50-Kg