A 10-kg mass and a 2.0-kg mass are connected by a light string over a massless,frictionless pulley.If g = 9.8 m/s²,what is the acceleration of the system when released? A)2.5 m/s² B)6.5 m/s² C)7.8 m/s² D)9.8 m/s²

Question

Quizplus · Accepted Answer

The acceleration of the system can be found using the equation:

a = (m1 - m2)g / (m1 + m2)

where m1 is the mass of the heavier object and m2 is the mass of the lighter object.

Plugging in the given values, we get:

a = (10 kg - 2.0 kg) * 9.8 m/s^2 / (10 kg + 2.0 kg)

a = (8.0 kg) * 9.8 m/s^2 / (12.0 kg)

a = 6.533 m/s^2

Rounding to the nearest tenth, we get:

a ≈ 6.5 m/s^2

Therefore, the best choice is B.

A 10-Kg Mass and a 2