Three identical 6.0-kg cubes are placed on a horizontal frictionless surface in contact with one another.The cubes are lined up from left to right and a 36-N force is applied to the left side of the left cube causing all three cubes to accelerate to the right.If the cubes are each subject to a frictional force of 6.0 N,what is the magnitude of the force exerted on the right cube by the middle cube in this case?
A)12 N
B)24 N
C)36 N
D)none of the above

Question

Quizplus · Accepted Answer

The force exerted on the right cube by the middle cube is equal to the force applied to the left cube minus the frictional force acting on the middle cube. So, the force exerted on the right cube is 36 N - 6 N = 30 N.

Three Identical 6