A baseball thrown from the outfield is released from shoulder height at an initial velocity of 29.4 m/s at an initial angle of 30.0 $\degree$ with respect to the horizontal.What is the maximum vertical displacement that the ball reaches during its trajectory?
A)11.0 m
B)9.80 m
C)22.1 m
D)44.1 m

Question

Quizplus · Accepted Answer

The maximum vertical displacement can be calculated using the formula: $ h = \frac{v^2 \sin^2(\theta)}{2g} $, where $ v = 29.4 \, \text{m/s} $, $ \theta = 30^\circ $, and $ g = 9.8 \, \text{m/s}^2 $. Plugging in the values, $ h = \frac{(29.4)^2 \times \sin^2(30^\circ)}{2 \times 9.8} = 11.0 \, \text{m} $.

A Baseball Thrown from the Outfield Is Released from Shoulder °\degree°

A Baseball Thrown from the Outfield Is Released from Shoulder $\degree$