A stone is thrown at an angle of 30 $\degree$ above the horizontal from the top edge of a cliff with an initial speed of 12 m/s.A stop watch measures the stone's trajectory time from top of cliff to bottom to be 5.6 s.How far out from the cliff's edge does the stone travel horizontally? (g = 9.8 m/s²and air resistance is negligible)

Question

Quizplus · Accepted Answer

The horizontal component of the initial velocity is 12 cos 30° = 10.4 m/s. The time of flight is 5.6 s. Therefore, the horizontal distance traveled by the stone is 10.4 m/s * 5.6 s = 58.24 m.

A Stone Is Thrown at an Angle of 30 °\degree° Above the Horizontal from the Top Edge of a Cliff

A Stone Is Thrown at an Angle of 30 $\degree$ Above the Horizontal from the Top Edge of a Cliff