Neglecting recoil of the gold nucleus,how much kinetic energy must an alpha particle (charge = 2 x 1.6 x 10-19 C) have to approach to within 1.00 ´ 10-14 m of a gold nucleus (charge = 79 x 1.6 x 10-19 C) ? (ke = 8.99 x 109 N*m2/C2 and 1 MeV = 1.6 x 10-13 J)
A) 11.7 MeV
B) 14.6 MeV
C) 18.2 MeV
D) 22.7 MeV
Correct Answer:
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