A hydrogen atom in the ground state absorbs a 12.75-eV photon.To what level is the electron promoted? (The ionization energy of hydrogen is 13.6-eV).
A)n = 2
B)n = 3
C)n = 4
D)n = 5

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The Answer of A hydrogen atom in the ground state absorbs a 12.75-eV photon.To what level is the electron promoted? (The ionization energy of hydrogen is 13.6-eV).
A)n = 2
B)n = 3
C)n = 4
D)n = 5

A Hydrogen Atom in the Ground State Absorbs a 12