The period of an oscillating weight on a spring in an inertial frame of reference is 0.80 s.What would be its speed if it were to move by an observer who measures its period as 1.2 s? (c = 3.00 x 10⁸ m/s) A)1.1 x l0⁸m/s B)2.2 x 10⁸ m/s C)2.5 x l0⁸ m/s D)2.9 x 10⁸ m/s

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Quizplus · Accepted Answer

The time dilation formula in special relativity is used: T' = T / sqrt(1 - v^2/c^2). Solving for v when T' = 1.2 s and T = 0.80 s gives v ≈ 2.2 x 10^8 m/s.

The Period of an Oscillating Weight on a Spring in an Inertial