If a proton with mass 1.67 x 10^-27 kg moves in an accelerator such that its total energy is three times its rest energy,what is its speed? (c = 3.00 x 10⁸ m/s) A)2.83 x 10⁸ m/s B)1.41 x 10⁸ m/s C)2.12 x 10⁸ m/s D)1.00 x 10⁸ m/s

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Quizplus · Accepted Answer

The total energy being three times the rest energy implies a relativistic factor (gamma) of 3. Using the formula for gamma, γ = 1/√(1-v²/c²), and solving for v, we find v ≈ 2.83 x 10⁸ m/s.

If a Proton with Mass 1