A Young's double-slit apparatus is set up so that a screen is positioned 1.6 m from the double slits,and the spacing between the two slits is 0.040 mm.What is the distance between alternating bright fringes on the screen if the light source has a wavelength of 630 nm? (1 nm = 10^-9 m) A)0.016 m B)0.025 m C)0.032 m D)0.047 m

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Quizplus · Accepted Answer

The distance between adjacent bright fringes is given by the formula: $\Delta y = \frac{\lambda L}{d}$, where $\lambda$ is the wavelength, $L$ is the distance between the screen and the double slits, and $d$ is the distance between the slits. Substituting the given values, we get: $\Delta y = \frac{(630	imes10^{-9})(1.6)}{0.040	imes10^{-3}} = 0.025	ext{ m}$. Therefore, the answer is B.

A Young's Double-Slit Apparatus Is Set Up So That a Screen