Light of wavelength 610 nm is incident on a slit of width 0.20 mm,and a diffraction pattern is produced on a screen that is 1.5 m from the slit.What is the distance of the second dark fringe from the center of the bright fringe? (1 nm = 10^-9 m) A)0.68 cm B)0.92 cm C)1.2 cm D)1.4 cm

Question

Quizplus · Accepted Answer

The distance of the n-th bright fringe from the center of the pattern is given by:

y = (nλL)/s

where y is the distance from the center of the pattern, λ is the wavelength of light, L is the distance from the slit to the screen, and s is the width of the slit.

The distance to the second dark fringe is given by:

y = (n+1/2)λL/s

We want to find y for n=2, so:

y = (2+1/2)610 nm * 1.5 m / 0.2 mm = 0.92 cm

Converting to scientific notation, we get:

y = 9.2 x 10^-3 m = 0.92 cm

Therefore, the answer is B.

Light of Wavelength 610 Nm Is Incident on a Slit