An oil film floats on a water surface.The indices of refraction for water and oil,respectively,are 1.333 and 1.466.If a ray of light is incident on the air-to-oil surface at an angle of 37.0 $\degree$ with the normal,what is the angle of the refracted ray in the water?
A)18.1 $\degree$
B)24.2 $\degree$
C)26.8 $\degree$
D)37.0 $\degree$

Question

Quizplus · Accepted Answer

Using Snell's Law, n1*sin(theta1) = n2*sin(theta2), where n1 = 1.466 (oil), theta1 = 37 degrees, and n2 = 1.333 (water). Solving for theta2 gives approximately 26.8 degrees.

An Oil Film Floats on a Water Surface °\degree° With the Normal,what Is the Angle of the Refracted Ray

An Oil Film Floats on a Water Surface $\degree$ With the Normal,what Is the Angle of the Refracted Ray