A solar cell has a light-gathering area of 10 cm² and produces 0.20 A at 0.80 V (dc)when illuminated with sunlight of intensity 1 000 W/m².What is the efficiency of the solar cell? A)16% B)7% C)23% D)4%

Question

Quizplus · Accepted Answer

First, we need to convert the light intensity from 1,000 W/m² to W/cm² by multiplying by 10,000 (since there are 10,000 cm² in 1 m²):
1,000 W/m² x (10,000 cm²/1 m²) = 10,000,000 W/cm²

Next, we can calculate the power output of the solar cell by multiplying the current (0.20 A) by the voltage (0.80 V):
Power = 0.20 A x 0.80 V = 0.16 W

Finally, we can calculate the efficiency by dividing the power output by the incident light power per unit area:
Efficiency = (0.16 W / 10 cm²) / (10,000,000 W/cm²) x 100% = 0.0016 / 1 x 100% = 0.16%

Therefore, the efficiency of the solar cell is 16%, which corresponds to answer choice C.

A Solar Cell Has a Light-Gathering Area of 10 Cm2

A Solar Cell Has a Light-Gathering Area of 10 Cm²