An emf of 0.32 V is induced in a 0.40-H inductor.What is the rate of change of current through the inductor?
A)0.80 A/s
B)0.13 A/s
C)1.3 A/s
D)0.64 A/s

Name: An emf of 0.32 V is induced in a 0.40-H inductor.What is the rate of change of current through the inductor? A)0.80 A/s B)0.13 A/s C)1.3 A/s D)0.64 A/s
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Question

Quizplus · Accepted Answer

The rate of change of current (di/dt) can be calculated using the formula emf = L * (di/dt), where L is the inductance. Rearranging gives di/dt = emf / L = 0.32 V / 0.40 H = 0.80 A/s.

An Emf of 0