A coaxial cable consists of a thin insulated straight wire carrying a current of 2.00 A surrounded by a cylindrical conductor carrying a current of 3.50 A in the opposite direction.The cylindrical conductor has a radius of 0.420 cm.What is the magnitude of the magnetic field between the inner and outer conductors at a distance of 0.300 cm from the central wire?

Question

Quizplus · Accepted Answer

Using the formula for the magnetic field within a coaxial cable:
B = (μ0/2π) * (I1/r1 - I2/r2)
where:
μ0 = permeability of free space = 4π×10^-7 Tm/A
I1 = current in the inner wire 
r1 = radius of the inner wire
I2 = current in the outer cylindrical conductor
r2 = radius of the outer cylindrical conductor
Plugging in the given values:
B = (μ0/2π) * (2.00/(0.300×10^-2) - 3.50/(0.420×10^-2))
B = 7.10×10^-5 T
Converting to scientific notation:
B = 11eaa64f_8fe8_89ed_a696_c931949ccea0_TB5258_11

A Coaxial Cable Consists of a Thin Insulated Straight Wire