Three 4.0-W resistors are connected in parallel to a 12.0-V battery.What is the current in any one of the resistors?
A)16 A
B)9.0 A
C)3.0 A
D)48 A

Question

Quizplus · Accepted Answer

The total resistance of the three resistors in parallel can be calculated using the formula:

1/R(total) = 1/R1 + 1/R2 + 1/R3

Substituting the values, we get:

1/R(total) = 1/4.0 + 1/4.0 + 1/4.0
1/R(total) = 3/4.0
R(total) = 4/3.0 = 1.33 Ω

Now, using Ohm's Law, we can calculate the current in any one of the resistors:

I = V/R
I = 12.0 V/4.0 Ω
I = 3.0 A

Therefore, the current in any one of the resistors is 3.0 A, which is option C.

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