Two resistors of values 6.0 and 12.0 W are connected in parallel.This combination in turn is hooked in series with a 4.0-W resistor.What is the overall resistance of this combination?
A)0.50 W
B)2.0 W
C)8.0 W
D)22.0 W

Question

Quizplus · Accepted Answer

When two resistors are connected in parallel, the equivalent resistance is found using the formula:
1/Req = (1/R1) + (1/R2)
Where Req is the equivalent resistance and R1 and R2 are the resistances of the two resistors.

Substituting the given values, we get:
1/Req = (1/6.0) + (1/12.0)
1/Req = 0.1667 + 0.0833
1/Req = 0.25

Req = 4.0 W

Now we have two resistors in series, so the equivalent resistance is found by simply adding the resistances:
Req = 4.0 + 8.0 = 12.0 W

Therefore, the overall resistance of the combination is 12.0 W.

Two Resistors of Values 6