Consider the circuit shown in the figure.What power is dissipated by the entire circuit?
A)14 W
B)28 W
C)52 W
D)112 W

Question

Consider the circuit shown in the figure.What power is dissipated by the entire circuit? 
A)14 W 
B)28 W 
C)52 W 
D)112 W

Quizplus · Accepted Answer

To solve for the total power, we first need to calculate the power dissipated in each resistor. Using Ohm's Law (P = V^2/R), we get:
-Power in 4 Ohm resistor = (6V)^2 / 4 Ohm = 9W
-Power in 2 Ohm resistor = (6V)^2 / 2 Ohm = 18W
-Power in 3 Ohm resistor = (6V)^2 / 3 Ohm = 12W

The total power is the sum of powers dissipated in each resistor, so we get:
Total power = 9W + 12W + 18W = 39W

However, we need to take into account that the 9V voltage source also dissipates power. The power dissipated in the voltage source is (9V * 2A) = 18W.

Therefore, the total power dissipated in the circuit is:
Total power = 39W + 18W = 57W

The closest answer choice is C) 52W.

Consider the Circuit Shown in the Figure