How much charge can be placed on a capacitor of plate area 10 cm² with air between the plates before it reaches "atmospheric breakdown" where E = 3.0 x 10⁶ V/m? (e₀ = 8.85 x 10^-12 C²/N*m²) A)2.7 x 10^-8 C B)4.0 x 10^-7 C C)5.3 x 10^-6 C D)6.6 x 10^-5 C

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Quizplus · Accepted Answer

The maximum charge is calculated using Q = ε₀ * A * E. Substituting the given values, Q = (8.85 x 10⁻¹² C²/N·m²) * (10 x 10⁻⁴ m²) * (3.0 x 10⁶ V/m) = 2.655 x 10⁻⁸ C, which rounds to 2.7 x 10⁻⁸ C.

How Much Charge Can Be Placed on a Capacitor of Plate