The electric field in a cathode ray tube is supposed to accelerate electrons from 0 to 1.60 x 10⁷m/s in a distance of 2.00 cm.What electric field is required? (m_e = 9.11 x 10^-31kg and e = 1.60 x 10^-19 C)

Question

Quizplus · Accepted Answer

We can use the equation:

acceleration = (electric field) x (charge of electron) / (mass of electron)

We are given the final velocity and distance, so we can find the acceleration:

a = v^2 / (2d) = (1.6 x 10^7 m/s)^2 / (2 x 0.02 m) = 1.28 x 10^12 m/s^2

Plugging in values, we get:

1.28 x 10^12 m/s^2 = (electric field) x (1.6 x 10^-19 C) / (9.11 x 10^-31 kg)

Solving for electric field, we get:

electric field = 36,400 N/C

Therefore, the best choice is C.

The Electric Field in a Cathode Ray Tube Is Supposed