A bat,flying at 5.00 m/s toward a wall,emits a chirp at 50.0 kHz.If the wall reflects this sound pulse,what is the frequency of the echo received by the bat? (v_sound = 340 m/s) A)51.5 kHz B)51.2 kHz C)40.8 kHz D)50.5 kHz

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Quizplus · Accepted Answer

The frequency of the echo can be calculated using the Doppler effect formula for sound. The bat is moving towards the wall, so the frequency increases. The formula is f' = f * (v + v0) / (v - vs), where f is the original frequency, v is the speed of sound, v0 is the speed of the observer (bat), and vs is the speed of the source (wall, which is 0). Substituting the values, f' = 50 kHz * (340 + 5) / (340 - 0) = 51.5 kHz.

A Bat,flying at 5