If a heat engine has an efficiency of 30% and its power output is 600 W,what is the rate of heat input from the combustion phase?

Question

Quizplus · Accepted Answer

The efficiency of a heat engine is defined as the ratio of the work output (in this case, 600 W) to the heat input. Therefore, we can write:
efficiency = work output / heat input
0.30 = 600 W / heat input
Solving for the heat input, we get:
heat input = 600 W / 0.30 = 2 000 W
So the rate of heat input from the combustion phase is 2 000 W. Therefore the correct answer is choice letter C.

If a Heat Engine Has an Efficiency of 30% and Its