During each cycle of operation a refrigerator absorbs 55 cal from the freezer compartment and expels 85 cal to the room.If one cycle occurs every 10 s,how many minutes will it take to freeze 500 g of water,initially at 0 $\degree$C? (L_v = 80 cal/g)

Question

Quizplus · Accepted Answer

The refrigerator needs to remove 80 cal/g to freeze water. For 500 g, it needs to remove 500 * 80 = 40,000 cal. The refrigerator removes 55 cal every 10 seconds, so it removes 55 * 6 = 330 cal per minute. Therefore, it will take 40,000 / 330 ≈ 121.21 minutes, which rounds to 120 minutes.

During Each Cycle of Operation a Refrigerator Absorbs 55 Cal °\degree°

During Each Cycle of Operation a Refrigerator Absorbs 55 Cal $\degree$