A 10-kg piece of aluminum (which has a specific heat of 900 J/kg* $\degree$C)is warmed so that its temperature increases by 5.0 C $\degree$.How much heat was transferred into it?

Question

Quizplus · Accepted Answer

The heat transferred can be calculated using the formula Q = mcΔT, where m = 10 kg, c = 900 J/kg°C, and ΔT = 5°C. Therefore, Q = 10 * 900 * 5 = 45,000 J or 4.5 x 10^4 J.

A 10-Kg Piece of Aluminum (Which Has a Specific Heat °\degree°

A 10-Kg Piece of Aluminum (Which Has a Specific Heat $\degree$