A puddle holds 150 g of water.If 0.50 g of water evaporates from the surface,what is the approximate temperature change of the remaining water? (L_v = 540 cal/g)

Question

Quizplus · Accepted Answer

First, we need to calculate the total amount of energy required to evaporate 0.5 g of water from the puddle:
0.5 g x 540 cal/g = 270 cal
Now, we can use the specific heat capacity of water (1 cal/g°C) to calculate the approximate temperature change of the remaining water:
Energy = mass x specific heat capacity x temperature change
270 cal = 150 g x 1 cal/g°C x temperature change
Temperature change = 270/150 = 1.8°C
Since the water lost energy, its temperature will decrease, so the answer is -1.8°C or -1.8°F. The correct answer is B.

A Puddle Holds 150 G of Water °\degree° B)-18 C °\degree° C)+018 C

A Puddle Holds 150 G of Water $\degree$ B)-18 C $\degree$ C)+018 C