Iced tea is made by adding ice to 1.8 kg of hot tea,initially at 80 $\degree$C.How many kg of ice,initially at 0 $\degree$C,are required to bring the mixture to 10 $\degree$C? (L_f = 3.33 ´ 10⁵ J/kg,c_w = 4 186 J/kg*(\degree\)C) A)1.8 kg B)1.6 kg C)1.4 kg D)1.2 kg

Question

Quizplus · Accepted Answer

To solve this problem, we will use the principle of conservation of energy. The energy released by the cooling tea will be taken up by the ice, causing it to melt. This means that the energy lost by the tea will be equal to the energy gained by the ice:

m tea x c tea x ΔT = m ice x c ice x ΔT

where m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

We want to find the mass of ice m ice required to bring the mixture to 10°F, so we rearrange the equation and substitute the given values:

m ice = (m tea x c tea x ΔT) / (c ice x ΔT)

m ice = (1.8 kg x 1.33 x 18°F) / (3.33 x 10^3 J/kg x °C x 10°F)

m ice ≈ 1.4 kg

Therefore, the answer is choice C - 1.4 kg of ice is required to bring the mixture to 10°F.

Iced Tea Is Made by Adding Ice to 1 °\degree° CHow Many Kg of Ice,initially at 0

Iced Tea Is Made by Adding Ice to 1 $\degree$ CHow Many Kg of Ice,initially at 0