The thermal conductivity of aluminum is 238 J/s*m* $\degree$C and of copper is 397 J/s*m*$\degree$C.A rod of each material is used as a heat conductor.If the rods have the same geometry and are used between the same temperature differences for the same time interval,what is the ratio of the heat transferred by the aluminum to the heat transferred by the copper?

Question

Quizplus · Accepted Answer

The heat transferred by a conductor is given by the equation Q = kA(dT/dx)t, where k is the thermal conductivity, A is the cross-sectional area, dT/dx is the temperature gradient, and t is the time interval. Since the rods have the same geometry and are used between the same temperature differences for the same time interval, the only difference between the two rods is their thermal conductivity. Therefore, the ratio of the heat transferred by the aluminum to the heat transferred by the copper is equal to the ratio of their thermal conductivities, which is 238 J/sF1F1F1S1F1F1F10mF1F1F1S1F1F1F10F1F1F1S1F1F1F10C / 397 J/sF1F1F1S1F1F1F10mF1F1F1S1F1F1F10F1F1F1S1F1F1F10C = 0.599.

The Thermal Conductivity of Aluminum Is 238 J/s*m °\degree° C and of Copper Is 397 J/s*m

The Thermal Conductivity of Aluminum Is 238 J/sm $\degree$ C and of Copper Is 397 J/sm