Suppose the ends of a 20-m-long steel beam are rigidly clamped at 0 $\degree$C to prevent expansion.The rail has a cross-sectional area of 30 cm².What force does the beam exert when it is heated to 40 $\degree$C? (a_steel = 1.1 x 10^-5/C $\degree$,Y_steel= 2.0 x 10¹¹ N/m²). A)2.6 x 10⁵N B)5.6 x 10⁴ N C)1.3 x 10³ N D)6.5 x 10² N

Question

Quizplus · Accepted Answer

The force exerted by the beam can be calculated using the formula F = A * Y * α * ΔT, where A is the cross-sectional area, Y is Young's modulus, α is the coefficient of linear expansion, and ΔT is the change in temperature. Substituting the given values: F = 30 x 10^-4 m^2 * 2.0 x 10^11 N/m^2 * 1.1 x 10^-5 /°C * (40°C - 0°C) = 2.6 x 10^5 N.

Suppose the Ends of a 20-M-Long Steel Beam Are Rigidly °\degree°

Suppose the Ends of a 20-M-Long Steel Beam Are Rigidly $\degree$