A pipe of length 10.0 m increases in length by 1.5 cm when its temperature is increased by 90 $\degree$F.What is its coefficient of linear expansion? A)30 x 10^-6/ $\degree$C B)17 x 10^-6/ $\degree$C C)13 x 10^-6/ $\degree$C D)23 x 10^-6/ $\degree$C

Question

Quizplus · Accepted Answer

We first convert the increase in length to meters:
1.5 cm = 0.015 m

We then convert the temperature increase to Celsius:
90°F = 32.2°C

Using the formula for linear expansion:
ΔL = αLΔT

where ΔL is the change in length, α is the coefficient of linear expansion, L is the original length, and ΔT is the change in temperature.

Plugging in the values we have:
0.015 m = α(10.0 m)(32.2°C)
Solving for α, we get:
α = 30 x 10^-6/°C

Converting this to the units in the answer choices:
α = 30 x 10^-6/°C = 30 x 10^-6/(1.8°F) = 16.7 x 10^-6/°F

Choice A is the closest to this value, so it is the best choice.

A Pipe of Length 10 °\degree° FWhat Is Its Coefficient of Linear Expansion? A)30 X 10-6

A Pipe of Length 10 $\degree$ FWhat Is Its Coefficient of Linear Expansion?
A)30 X 10^-6