Two moles of nitrogen gas are contained in an enclosed cylinder with a movable piston.If the gas temperature is 298 K,and the pressure is 1.01 x 10⁶ N/m²,what is the volume? (R = 8.31 J/mol*K) A)9.80 x 10^-3m³ B)4.90 x 10^-3 m³ C)17.3 x 10^-3m³ D)8.31 x 10^-3 m³

Question

Quizplus · Accepted Answer

Using the ideal gas law, PV = nRT, we can solve for the volume:
V = (nRT)/P = ((2 mol)(8.31 J/mol*K)(298 K))/(1.01 x 10^16 N/m^2) = 4.90 x 10^-3 m^3 = 4.90 x 10^-3 x 10^3 = 4.90 x 10^-6 m^3 = 4.90 x 10^-3 L = 4.90 mL
Therefore, the best choice is B, which is 4.90 x 10^-3 m^3 or 4.90 mL.

Two Moles of Nitrogen Gas Are Contained in an Enclosed