The function prototype double mySqrt(int x);
A) Declares a function called mySqrt which takes an integer as an argument and returns a double.
B) Defines a function called double which calculates square roots.
C) Defines a function called mySqrt which takes an argument of type x and returns a double.
D) Declares a function called mySqrt which takes a double as an argument and returns an integer.

Question

Quizplus · Accepted Answer

The function prototype declares a function called mySqrt which takes an integer as an argument and returns a double. It does not define the function or calculate square roots.

The Function Prototype Double MySqrt(int X);