Starting with the expression for work , one can change the look of the expression without changing what it represents by dividing the force F by the area it is applied over and multiplying the differential distance dx by that same area. Force divided by area is a pressure (P), and area times the differential distance is a differential volume. Hence one can also describe work as . A gas at constant temperature will change its pressure inversely to changes in volume, . If a sample of gas has a pressure of 1 atmosphere when its volume is 1 L, how much work does it do when it expands from 1 L to 3 L?

Question

Starting with the expression for work  , one can change the look of the expression without changing what it represents by dividing the force F by the area it is applied over and multiplying the differential distance dx by that same area. Force divided by area is a pressure (P), and area times the differential distance is a differential volume. Hence one can also describe work as  . A gas at constant temperature will change its pressure inversely to changes in volume,  . If a sample of gas has a pressure of 1 atmosphere when its volume is 1 L, how much work does it do when it expands from 1 L to 3 L?

Quizplus · Accepted Answer

The Answer of Starting with the expression for work  , one can change the look of the expression without changing what it represents by dividing the force F by the area it is applied over and multiplying the differential distance dx by that same area. Force divided by area is a pressure (P), and area times the differential distance is a differential volume. Hence one can also describe work as  . A gas at constant temperature will change its pressure inversely to changes in volume,  . If a sample of gas has a pressure of 1 atmosphere when its volume is 1 L, how much work does it do when it expands from 1 L to 3 L?

Starting with the Expression for Work , One Can