A projectile is fired with initial speed feet per second from a height of h feet at an angle of above the horizontal. Assuming that the only force acting on the object is gravity, find the horizontal range. Round to the nearest tenth of a foot.

Question

A projectile is fired with initial speed  feet per second from a height of h feet at an angle of  above the horizontal. Assuming that the only force acting on the object is gravity, find the horizontal range. Round to the nearest tenth of a foot.

Quizplus · Accepted Answer

The horizontal range, R, can be found using the equation:
R = (v^2/g) * sin(2θ)
where v is the initial speed, θ is the angle above the horizontal, and g is the acceleration due to gravity.

In this problem, v = 11eaa88b_9374_14df_a696_73cb7c5eff92_TB5869_11 ft/s and θ = 11eaa88b_9374_14e0_a696_c909b4517a71_TB5869_11. The acceleration due to gravity is approximately 32.2 ft/s^2.

Using the equation, we get:
R = (11eaa88b_9374_14df_a696_73cb7c5eff92_TB5869_11^2/32.2) * sin(2 * 11eaa88b_9374_14e0_a696_c909b4517a71_TB5869_11)
R ≈ 2127.5 ft

Rounding to the nearest tenth of a foot gives us the answer of D) 2127.5 ft.

A Projectile Is Fired with Initial Speed Feet Per