Find proj_ba for the given vectors.

Question

Quizplus · Accepted Answer

- projS1U1B1bS1U1B0S1U1B1 is the projection of b onto the plane spanned by S1U1B0 and S1U1B1. 
- S1U1B0a is the vector connecting S1U1B0 to a. 
- To find the projection, we need to find the component of S1U1B0a that lies on the plane spanned by S1U1B0 and S1U1B1. 
- This component is given by the cross product of S1U1B0a and the normal vector to the plane, which is given by the cross product of S1U1B0S1U1B1 and S1U1B0S1U1B0. 
- Therefore, projS1U1B1bS1U1B0S1U1B1 S1U1B0a = a - (a dot (S1U1B0S1U1B1 cross S1U1B0S1U1B0)) * (S1U1B0S1U1B1 cross S1U1B0S1U1B0) / |S1U1B0S1U1B1 cross S1U1B0S1U1B0|^2. 
- Plugging in the given vectors, we get C as the correct choice.

Find Projb a for the Given Vectors

Find Proj_ba for the Given Vectors