Cesium chloride adopts a simple cubic lattice where the eight Cl^- ions lie at the corners of the cubic unit cell and the Cs⁺ ion lies in the center of the cube.If the edge length of the unit cell is approximately 412.3 pm and the ionic radius of Cl^- is about 181 pm,calculate an estimate of the ionic radius of Cs⁺.

Question

Quizplus · Accepted Answer

The Cs ion is located at the center of the cube, so the distance from one Cs ion to its nearest Cl ion in the cube can be calculated as follows:
Cs-Cl distance = (edge length of the unit cell)/2 - ionic radius of Cl
= 412.3 pm/2 - 181 pm
= 25.15 pm
Therefore, the Cs ion radius can be calculated by subtracting this distance from the edge length of the unit cell:
Cs ion radius = (edge length of the unit cell)/2 - Cs-Cl distance
= 412.3 pm/2 - 25.15 pm
= 176.0 pm
Therefore, the best choice is D) 176 pm.

Cesium Chloride Adopts a Simple Cubic Lattice Where the Eight