If an X-ray with a wavelength of 154 pm is diffracted at an angle 2$\theta$ = 14.6 $\circ$ ,according to the Bragg equation (n$\lambda$ = 2 d sin$\theta$ ),what is the distance between layers of the crystal that give rise to this diffraction? Assume n = 1 in this problem.

Question

If an X-ray with a wavelength of 154 pm is diffracted at an angle 2$\theta$  = 14.6 $\circ$ ,according to the Bragg equation (n$\lambda$ = 2 d sin$\theta$  ),what is the distance between layers of the crystal that give rise to this diffraction? Assume n = 1 in this problem.

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The Answer of If an X-ray with a wavelength of 154 pm is diffracted at an angle 2$\theta$  = 14.6 $\circ$ ,according to the Bragg equation (n$\lambda$ = 2 d sin$\theta$  ),what is the distance between layers of the crystal that give rise to this diffraction? Assume n = 1 in this problem.

If an X-Ray with a Wavelength of 154 Pm Is θ\thetaθ

If an X-Ray with a Wavelength of 154 Pm Is $\theta$