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Arsenic Acid Is a Triprotic Acid in Water,ionizing in the Following

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Arsenic acid is a triprotic acid in water,ionizing in the following sequential steps:
H3AsO4 + H2O \leftrightarrows H2AsO4- + H3O+
 Arsenic acid is a triprotic acid in water,ionizing in the following sequential steps: H<sub>3</sub>AsO<sub>4</sub> + H<sub>2</sub>O  \leftrightarrows H<sub>2</sub>AsO<sub>4</sub><sup>-</sup> + H<sub>3</sub>O<sup>+ </sup> <sup> </sup>   = 5.5 *10 <sup>-</sup> <sup>3</sup> H<sub>2</sub>AsO<sub>4</sub><sup>-</sup> + H<sub>2</sub>O  \leftrightarrows HAsO<sub>4</sub><sup>2</sup><sup>-</sup> + H<sub>3</sub>O<sup>+ </sup> <sup> </sup>   = 1.7 *10<sup>-</sup><sup>7</sup> HAsO<sub>4</sub><sup>2</sup><sup>-</sup> + H<sub>2</sub>O  \leftrightarrows AsO<sub>4</sub><sup>3</sup><sup>-</sup> + H<sub>3</sub>O<sup>+ </sup> <sup> </sup>   = 5.1 * 10<sup>-</sup><sup>12</sup> What is the approximate pH of a 0.80 M Na<sub>3</sub>AsO<sub>4</sub> solution? = 5.5 *10 - 3
H2AsO4- + H2O \leftrightarrows HAsO42- + H3O+
 Arsenic acid is a triprotic acid in water,ionizing in the following sequential steps: H<sub>3</sub>AsO<sub>4</sub> + H<sub>2</sub>O  \leftrightarrows H<sub>2</sub>AsO<sub>4</sub><sup>-</sup> + H<sub>3</sub>O<sup>+ </sup> <sup> </sup>   = 5.5 *10 <sup>-</sup> <sup>3</sup> H<sub>2</sub>AsO<sub>4</sub><sup>-</sup> + H<sub>2</sub>O  \leftrightarrows HAsO<sub>4</sub><sup>2</sup><sup>-</sup> + H<sub>3</sub>O<sup>+ </sup> <sup> </sup>   = 1.7 *10<sup>-</sup><sup>7</sup> HAsO<sub>4</sub><sup>2</sup><sup>-</sup> + H<sub>2</sub>O  \leftrightarrows AsO<sub>4</sub><sup>3</sup><sup>-</sup> + H<sub>3</sub>O<sup>+ </sup> <sup> </sup>   = 5.1 * 10<sup>-</sup><sup>12</sup> What is the approximate pH of a 0.80 M Na<sub>3</sub>AsO<sub>4</sub> solution? = 1.7 *10-7
HAsO42- + H2O \leftrightarrows AsO43- + H3O+
 Arsenic acid is a triprotic acid in water,ionizing in the following sequential steps: H<sub>3</sub>AsO<sub>4</sub> + H<sub>2</sub>O  \leftrightarrows H<sub>2</sub>AsO<sub>4</sub><sup>-</sup> + H<sub>3</sub>O<sup>+ </sup> <sup> </sup>   = 5.5 *10 <sup>-</sup> <sup>3</sup> H<sub>2</sub>AsO<sub>4</sub><sup>-</sup> + H<sub>2</sub>O  \leftrightarrows HAsO<sub>4</sub><sup>2</sup><sup>-</sup> + H<sub>3</sub>O<sup>+ </sup> <sup> </sup>   = 1.7 *10<sup>-</sup><sup>7</sup> HAsO<sub>4</sub><sup>2</sup><sup>-</sup> + H<sub>2</sub>O  \leftrightarrows AsO<sub>4</sub><sup>3</sup><sup>-</sup> + H<sub>3</sub>O<sup>+ </sup> <sup> </sup>   = 5.1 * 10<sup>-</sup><sup>12</sup> What is the approximate pH of a 0.80 M Na<sub>3</sub>AsO<sub>4</sub> solution? = 5.1 * 10-12
What is the approximate pH of a 0.80 M Na3AsO4 solution?

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