Arsenic acid is a triprotic acid in water,ionizing in the following sequential steps:
H3AsO4 + H2O H2AsO4- + H3O+
= 5.5 *10 - 3
H2AsO4- + H2O HAsO42- + H3O+
= 1.7 *10-7
HAsO42- + H2O AsO43- + H3O+
= 5.1 * 10-12
What is the approximate pH of a 0.80 M Na3AsO4 solution?
Correct Answer:
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