For the following hypothetical equilibrium,A + 2 B $\leftrightarrows$ C,what is the value of the equilibrium constant if the concentrations at equilibrium are [A] = 4.5 * 10^-⁵ M,[B] = 2.2 *10^-² M,and [C] = 9.4 * 10^-³ M?

Question

Quizplus · Accepted Answer

The equilibrium constant, Kc, is calculated by taking the concentrations of the products raised to their stoichiometric coefficients, divided by the concentrations of the reactants raised to their stoichiometric coefficients: Kc = ([C]^1)/([A]^1[B]^2) Plugging in the given concentrations, we get: Kc = (9.4x10^-15)/(4.5x10^-10 x (2.2x10^-10)^2) Kc = 4.3x10^-5 or 4.3 F1F1F1S1F1F1F10 10⁵ (in scientific notation)

For the Following Hypothetical Equilibrium,A + 2 B ⇆\leftrightarrows⇆ C,what Is the Value of the Equilibrium Constant If the Is

For the Following Hypothetical Equilibrium,A + 2 B $\leftrightarrows$ C,what Is the Value of the Equilibrium Constant If the Is