Consider the Following Equilibrium: CO(g)+ 3 H₂(g) $\leftrightarrows$ CH₄(g)+ H₂O(g) $\times$ 10^-5 at 1400

Consider the following equilibrium: CO(g) + 3 H₂(g) $\leftrightarrows$ CH₄(g) + H₂O(g) .If K_p = 1.61 $\times$ 10^-5 at 1400.0 K,calculate K_c.

A) 1.40 $\times$ 10^-7
B) 1.85 $\times$ 10^-3
C) 541
D) 0.212
E) 1.22 $\times$ 10^-9