The Equilibrium Constant for the Formation of Calcium Carbonate from the Ions

The equilibrium constant for the formation of calcium carbonate from the ions in solution is 2.2 $\times$ 10⁸ according to the reaction Ca²⁺(aq) + CO₃^2-(aq) $\leftrightarrows$ CaCO₃(s) .What is the value of the equilibrium constant for the reverse of this reaction?

A) the same,2.2 $\times$ 10⁸
B) -2.2 $\times$ 10⁸
C) 2.2 $\times$ 10^-8
D) 4.5 $\times$ 10^-9
E) 4.5 $\times$ 10⁹