The mechanism for the reaction H₂(g)+ 2 ICl(I)$\to$ 2 HCl(g)+ I₂(g)is proposed to be: Step 1: H₂(g)+ ICl(g)$\to$ HI(g)+ HCl(g)(slow) Step 2: HI(g)+ ICl(g)$\to$ I₂(g)+HCl(g)(fast) What is the molecularity of the rate-determining step?

Question

Quizplus · Accepted Answer

The rate-determining step is the slowest step, which is Step 1. It involves two reactant molecules, H2 and ICl, making it bimolecular.

The Mechanism for the Reaction H2(g)+ 2 ICl(I) →\to→ 2 HCl(g)+ I2(g)is Proposed to Be: Step 1: H2(g)+ ICl(g)

The Mechanism for the Reaction H₂(g)+ 2 ICl(I) $\to$ 2 HCl(g)+ I₂(g)is Proposed to Be: Step 1: H₂(g)+ ICl(g)