The enthalpy of fusion for benzene is 127.34 kJ/kg,and its melting point is 5.49 $\circ$ C.What is the entropy change when 1 mole of benzene melts at 5.49 $\circ$ C?

Question

Quizplus · Accepted Answer

The entropy change (ΔS) can be calculated using the formula ΔS = ΔH/T, where ΔH is the enthalpy of fusion and T is the temperature in Kelvin. First, convert the melting point from Celsius to Kelvin (5.49°C + 273.15 = 278.64 K). Then, convert the enthalpy of fusion from kJ/kg to J/mol using the molar mass of benzene (78.11 g/mol). ΔH = 127.34 kJ/kg * 78.11 g/mol * 1000 J/kJ / 1000 g/kg = 9950.5 J/mol. Finally, ΔS = 9950.5 J/mol / 278.64 K = 35.696 J/K.

The Enthalpy of Fusion for Benzene Is 127 ∘\circ∘ CWhat Is the Entropy Change When 1 Mole of Benzene

The Enthalpy of Fusion for Benzene Is 127 $\circ$ CWhat Is the Entropy Change When 1 Mole of Benzene