What would be the freezing point of a 1.00 m solution of KCl in water? (K_f= 1.86 $\circ$ C)

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Quizplus · Accepted Answer

The freezing point depression is calculated using ΔTf = i * Kf * m, where i is the van't Hoff factor (2 for KCl), Kf is the freezing point depression constant (1.86°C/m), and m is the molality (1.00 m). Thus, ΔTf = 2 * 1.86 * 1.00 = 3.72°C. The freezing point of pure water is 0°C, so the solution's freezing point is 0 - 3.72 = -3.72°C.

What Would Be the Freezing Point of a 1 ∘\circ∘ C) A)0

What Would Be the Freezing Point of a 1 $\circ$ C)
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